Class 11 Physics CBSE Format

CBSE Class 11 Physics Important Questions: Chapter-wise for Boards and Exams

Updated for 2025–2026 Board Pattern · 11 Views

CBSE Class 11 Physics Important Questions: Chapter-wise for Boards and Exams (2025–2026)

Mastering CBSE Class 11 Physics is vital for scoring top marks in your 2025–2026 annual school examinations and establishing the conceptual foundation required for Class 12 board exams, JEE, and NEET. The Class 11 physics curriculum transitions students from general science to rigorous mathematical modeling, derivations, and problem-solving. This guide delivers a curated, chapter-wise breakdown of high-weightage concepts, essential derivations, and important CBSE Class 11 Physics questions with complete, step-by-step solutions aligned with the latest NCERT syllabus.

Key Concepts and High-Weightage Chapters in CBSE Class 11 Physics

The CBSE Class 11 Physics syllabus is divided into major units, each testing distinct competencies ranging from vector mechanics to thermodynamic laws and wave kinematics. To optimize your revision, focus on the core principles and mathematical derivations outlined below.

1. Mechanics (Kinematics, Dynamics, and Gravitation)

Mechanics forms over 40% of the Class 11 curriculum. Essential theoretical foundations include:

  • Equations of Motion: Derivations using calculus methods: v = u + at, s = ut + ½at2, and v2 = u2 + 2as.
  • Projectile Motion: Trajectory equation y = x tan θ - [g / (2u2 cos2 θ)] x2, maximum height H = (u2 sin2 θ) / (2g), and horizontal range R = (u2 sin 2θ) / g.
  • Newton's Laws and Friction: Free-body diagrams, static vs. kinetic friction (μs ≥ μk), and banking of roads.
  • Work-Energy Theorem: Equating work done by variable forces to the change in kinetic energy: W = ∫ F dx = ΔK.
  • Rotational Dynamics: Torque (τ = Iα), angular momentum conservation (L = Iω = \text{constant}), and moment of inertia for standard geometric bodies.
  • Gravitation: Kepler’s laws, variation of g with altitude (gh ≈ g(1 - 2h/R)) and depth (gd = g(1 - d/R)), and escape velocity (ve = √(2GM/R)).

2. Concept Deep Dive: Maximum Safe Speed on a Banked Road with Friction

Consider a vehicle of mass m navigating a curved track of radius R banked at an angle θ with a coefficient of static friction μ.

  1. Resolving vertical forces for equilibrium:
    N cos θ = mg + fs sin θ = mg + μ N sin θ &implies; N (cos θ - μ sin θ) = mg
  2. Resolving horizontal forces providing centripetal acceleration:
    N sin θ + fs cos θ = (m vmax2) / R &implies; N (sin θ + μ cos θ) = (m vmax2) / R
  3. Dividing the horizontal equation by the vertical equation eliminates the normal reaction N:
    (vmax2) / (R g) = (sin θ + μ cos θ) / (cos θ - μ sin θ) = (tan θ + μ) / (1 - μ tan θ)
  4. Solving for maximum velocity gives:
    vmax = √[R · g · (tan θ + μ) / (1 - μ tan θ)]

3. Properties of Bulk Matter and Thermodynamics

  • Fluid Mechanics: Pascal’s law, Equation of Continuity (A1v1 = A2v2), Bernoulli’s theorem (P + ½ρv2 + ρgh = \text{constant}), and Stokes' law of viscosity with terminal velocity derivation.
  • Thermal Physics & Thermodynamics: First Law of Thermodynamics (ΔQ = ΔU + ΔW), work done during isothermal expansion (W = 2.303 nRT log10(V2/V1)) versus adiabatic expansion (W = [nR(T1 - T2)] / (γ - 1)).

4. Oscillations and Waves

  • Simple Harmonic Motion (SHM): Differential equation d2x/dt2 + ω2x = 0, total mechanical energy in SHM (E = ½ m ω2 A2), and time period of a simple pendulum (T = 2π√(L/g)).
  • Wave Mechanics: Progressive wave equation y = A sin(kx - ωt + φ), standing waves in open and closed organ pipes, and beat frequency formula (fbeat = |f1 - f2|).

Important CBSE Questions with Answers (Chapter-Wise)

Chapter 2: Units and Measurements

Question 1 (2 Marks): The velocity v of water waves depends on wavelength λ, density of water ρ, and acceleration due to gravity g. Deduce the relationship using dimensional analysis.

Answer:

  1. Let v = k · λa · ρb · gc, where k is a dimensionless constant.
  2. Write dimensions for each physical quantity:
    [v] = [M0 L T-1]
    [λ] = [L], [ρ] = [M L-3], [g] = [L T-2]
  3. Equate dimensions on both sides:
    [M0 L1 T-1] = [L]a [M L-3]b [L T-2]c = [Mb La - 3b + c T-2c]
  4. Comparing powers of M, L, and T:
    For M: b = 0 (Velocity does not depend on density).
    For T: -2c = -1 &implies; c = 1/2.
    For L: a - 3b + c = 1 &implies; a - 0 + 1/2 = 1 &implies; a = 1/2.
  5. Substituting the values yields: v = k √(λ g).

Chapter 4: Motion in a Plane

Question 2 (3 Marks): A projectile is fired with a velocity u at an angle θ to the horizontal. Prove that its trajectory is parabolic and find the angle of projection for which horizontal range equals maximum height.

Answer:

  1. Position coordinates at time t:
    Horizontal displacement: x = (u cos θ) t &implies; t = x / (u cos θ).
    Vertical displacement: y = (u sin θ) t - ½ g t2.
  2. Substitute t into the vertical equation:
    y = (u sin θ) · [x / (u cos θ)] - ½ g [x / (u cos θ)]2
    y = x tan θ - [g / (2u2 cos2 θ)] x2
    Since this equation is of the form y = Ax - Bx2, the trajectory is a parabola.
  3. Condition when Horizontal Range (R) equals Maximum Height (H):
    R = (u2 sin 2θ) / g = (2 u2 sin θ cos θ) / g
    H = (u2 sin2 θ) / (2g)
    Setting R = H:
    (2 u2 sin θ cos θ) / g = (u2 sin2 θ) / (2g)
    2 cos θ = (sin θ) / 2 &implies; tan θ = 4 &implies; θ = tan-1(4) ≈ 75.96°.

Chapter 6: Work, Energy, and Power

Question 3 (3 Marks): State and prove the Work-Energy Theorem for a variable force in one dimension.

Answer:

  1. Statement: The work done by the net force acting on a body is equal to the change in kinetic energy of the body: W = ΔK = Kf - Ki.
  2. Proof: Kinetic energy is given by K = ½ m v2.
  3. Differentiating K with respect to time t:
    dK/dt = ½ m · 2v · (dv/dt) = m · v · a = (m · a) · v = F · (dx/dt)
  4. Multiplying both sides by dt:
    dK = F dx
  5. Integrating from initial state (xi, Ki) to final state (xf, Kf):
    KiKf dK = ∫xixf F dx
    Kf - Ki = W. Hence proved.

Chapter 7: System of Particles and Rotational Motion

Question 4 (3 Marks): State the law of conservation of angular momentum. A horizontal disc rotates freely about a vertical axis passing through its centre with angular velocity ω1. A child of mass m gently sits on the edge of the disc. What will be the new angular speed if the moment of inertia of the disc alone is I and its radius is R?

Answer:

  1. Law of Conservation of Angular Momentum: If no external torque acts on a system (τext = 0), the total angular momentum of the system remains constant: L = I ω = \text{constant}.
  2. Initial angular momentum: Linitial = I ω1.
  3. When the child sits at the edge at distance R, the new moment of inertia is:
    Itotal = I + m R2.
  4. Applying conservation of angular momentum:
    I ω1 = (I + m R2) ω2
  5. Solving for the new angular speed:
    ω2 = [I / (I + m R2)] ω1.

Chapter 10: Mechanical Properties of Fluids

Question 5 (5 Marks): State Bernoulli's principle. Derive Bernoulli's equation for the streamline flow of an ideal, incompressible, and non-viscous fluid.

Answer:

  1. Statement: For the streamline flow of an ideal (incompressible and non-viscous) fluid, the sum of pressure energy, kinetic energy per unit volume, and potential energy per unit volume remains constant along a streamline:
    P + ½ ρ v2 + ρ g h = constant.
  2. Derivation: Consider a tube of flow with cross-sectional areas A1 and A2 at heights h1 and h2 above a reference level.
    Let fluid enter section 1 with speed v1 at pressure P1, and exit section 2 with speed v2 at pressure P2.
  3. In time interval Δt, the mass of fluid entering is Δm = ρ A1 v1 Δt = ρ A2 v2 Δt (by equation of continuity). Volume ΔV = Δm / ρ.
  4. Work done on the fluid at section 1: W1 = P1 A1 (v1 Δt) = P1 ΔV.
    Work done by the fluid at section 2: W2 = P2 A2 (v2 Δt) = P2 ΔV.
    Net work done on the fluid: Wnet = (P1 - P2) ΔV.
  5. Change in Kinetic Energy: ΔK = ½ Δm (v22 - v12).
  6. Change in Potential Energy: ΔU = Δm g (h2 - h1).
  7. According to the Work-Energy Theorem (Wnet = ΔK + ΔU):
    (P1 - P2) ΔV = ½ Δm (v22 - v12) + Δm g (h2 - h1)
  8. Divide both sides by ΔV (noting that Δm / ΔV = ρ):
    P1 - P2 = ½ ρ v22 - ½ ρ v12 + ρ g h2 - ρ g h1
  9. Rearranging terms with identical subscripts:
    P1 + ½ ρ v12 + ρ g h1 = P2 + ½ ρ v22 + ρ g h2. Hence proved.

Chapter 12: Thermodynamics

Question 6 (3 Marks): Derive an expression for the work done during the isothermal reversible expansion of an ideal gas from volume V1 to V2 at constant temperature T.

Answer:

  1. For n moles of an ideal gas, the equation of state is PV = nRT &implies; P = (nRT) / V.
  2. Work done during an infinitesimal expansion dV: dW = P dV = (nRT / V) dV.
  3. Total work done expanding from volume V1 to V2:
    W = ∫V1V2 (nRT / V) dV = nRT ∫V1V2 (1 / V) dV
  4. Evaluating the integral:
    W = nRT [ln V]V1V2 = nRT ln(V2 / V1)
  5. Converting natural logarithm to base 10:
    W = 2.303 nRT log10(V2 / V1)
    Since P1V1 = P2V2 &implies; V2/V1 = P1/P2, this can also be written as:
    W = 2.303 nRT log10(P1 / P2).

How to Prepare for CBSE Class 11 Physics Exams (2025–2026)

Excelling in the Class 11 Physics exam requires a balanced strategy combining theoretical clarity, systematic derivation practice, and numerical precision. Follow these actionable steps:

  • Master Standard Derivations: Physics question papers allocate roughly 20–25 marks to direct derivations (such as Banking of Roads, Projectile Trajectory, Work-Energy Theorem, Terminal Velocity, and Bernoulli's Theorem). Practice writing each derivation with clearly labeled diagrams and explicit assumptions.
  • Adopt Step-Wise Numerical Writing: CBSE marking schemes award partial credit for:
    1. Listing given data and conversions to standard SI units.
    2. Writing the governing formula.
    3. Proper mathematical substitution.
    4. Final answer highlighted with correct units and significant figures.
  • Maintain a Formula and Dimensional Sheet: Maintain a dedicated notebook for quick revision containing SI units, dimensional formulas, and conditions of applicability for every equation across all 15 chapters.
  • Solve NCERT In-Text, Exercise, and Exemplar Problems: Over 70% of board and school examination questions are directly adapted from NCERT textbook exercises and NCERT Exemplar problems.

Where to Practice More

To evaluate your preparation and improve time management under actual exam conditions, practice solving chapter-wise test papers and full-syllabus mock tests. Generate customized, blueprint-aligned CBSE sample papers, previous years' questions, and verified step-by-step marking scheme solutions at Theorify QPTool (qptool.theorify.in).

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